If a 12V product dissipates 50W, what is the load resistance it represents?

If a 12V product dissipates 50W, what is the load resistance it represents?

• A. 1.5 ohms
• B. 2.9 ohms
• C. 5.4 ohms
• D. 12 ohms

Answer: (B)

To determine the load resistance represented by a product that operates at 12V while dissipating 50W, we can use Ohm's law and the power equation. Power (P) can be calculated using the formula: \[ P = \frac{V^2}{R} \] Where 'V' is the voltage and 'R' is the resistance. To find the resistance, we can rearrange this formula: \[ R = \frac{V^2}{P} \] Substituting the given values into the equation, we have: \[ R = \frac{(12V)^2}{50W} = \frac{144}{50} = 2.88 \text{ ohms} \] When rounded to one decimal place, this value is approximately 2.9 ohms. Therefore, the load resistance it represents is approximately 2.9 ohms, making the calculation consistent with option B. The calculations confirm that the resistance is determined accurately based on the given power and voltage parameters.

To determine the load resistance represented by a product that operates at 12V while dissipating 50W, we can use Ohm's law and the power equation. Power (P) can be calculated using the formula:

[ P = \frac{V^2}{R} ]

Where 'V' is the voltage and 'R' is the resistance. To find the resistance, we can rearrange this formula:

[ R = \frac{V^2}{P} ]

Substituting the given values into the equation, we have:

[ R = \frac{(12V)^2}{50W} = \frac{144}{50} = 2.88 \text{ ohms} ]

When rounded to one decimal place, this value is approximately 2.9 ohms. Therefore, the load resistance it represents is approximately 2.9 ohms, making the calculation consistent with option B. The calculations confirm that the resistance is determined accurately based on the given power and voltage parameters.