Doubling the power in a transmitter output signal results in how many dB gain?

Doubling the power in a transmitter output signal results in how many dB gain?

• A. 1
• B. 3
• C. 6
• D. 10

Answer: (B)

When discussing power levels in decibels (dB), it is important to understand the logarithmic nature of the dB measurement. Specifically, the formula for calculating gain in decibels when dealing with power is: \[ \text{Gain (dB)} = 10 \cdot \log_{10}(\frac{P_2}{P_1}) \] If we are doubling the power (meaning \(P_2 = 2 \cdot P_1\)), we can substitute this into the formula: \[ \text{Gain (dB)} = 10 \cdot \log_{10}(2) \] The logarithm of 2 (approximately 0.301) gives us: \[ \text{Gain (dB)} = 10 \cdot 0.301 \approx 3.01 \text{ dB} \] For practical purposes, we can round this to 3 dB. Thus, when the power output of a transmitter is doubled, it results in a gain of approximately 3 dB. This is a fundamental principle in electronics and telecommunications that helps in quantifying changes in power levels. The gain of 3 dB signifies that there is a

When discussing power levels in decibels (dB), it is important to understand the logarithmic nature of the dB measurement. Specifically, the formula for calculating gain in decibels when dealing with power is:

[ \text{Gain (dB)} = 10 \cdot \log_{10}(\frac{P_2}{P_1}) ]

If we are doubling the power (meaning (P_2 = 2 \cdot P_1)), we can substitute this into the formula:

[ \text{Gain (dB)} = 10 \cdot \log_{10}(2) ]

The logarithm of 2 (approximately 0.301) gives us:

[ \text{Gain (dB)} = 10 \cdot 0.301 \approx 3.01 \text{ dB} ]

For practical purposes, we can round this to 3 dB. Thus, when the power output of a transmitter is doubled, it results in a gain of approximately 3 dB. This is a fundamental principle in electronics and telecommunications that helps in quantifying changes in power levels.

The gain of 3 dB signifies that there is a